Category Archives: Math 11

core competency math 11

Posted on by under Math 11, Self-Assessment, Uncategorized
Name: Katelyn Simmons Date:

 

 

 

 

How does the artifact you selected demonstrate strengths & growth in the communication competency?

 

In what ways might you further develop your communication competency?

 Self-Reflection

Describe how the artifact you selected shows your strengths & growth in specific core competencies. The prompt questions on the left – or other self-assessment activities you may have done – may guide your reflection process.

 

My unit test on quadratics and rational expressions.

I chose these two unit tests because for my quadratics test I got my well deserved A. I studied hard asked many questions and we spent quite a lot of time working on the unit. Which helped me continue my understanding to prepare for the test. For rational expressions I did not do so well as we did not have any time in class or at all to catch up with the learning which made it very hard. Next time I will go to Vandercran earlier as she helped me so much. A strength that I need to work on is asking more questions and one I did very well is that I did all my homework.

 

 

 

How does the artifact you selected demonstrate strengths & growth in the thinking competencies?

 

In what ways might you further develop your thinking competencies?

 

 

 

How does the artifact you selected demonstrate strengths & growth in the personal & social competencies?

 

In what ways might you further develop your personal & social competencies?

 

Publish Your Self Assessment

You will now attach and/or embed your self-assessment to the bottom of the blog post with the artifact you have chosen. You may choose to make this post private or public. After placing your artifact on a blog post, follow the instructions below.

  1. Categories – Self-Assessment
  2. Tags – Now tag your post using the tag that corresponds to the competency that you have written about. You can choose more than one. Please use lower case letters and be exact.
    • #creativethinkingcc
    • #communicationcc
    • #criticalthinkingcc
    • #socialresponsibilitycc
    • #personalidentitycc
    • #personalawarenesscc
  3. Use the Add Document button located at the top of your post page and embed your self-assessment at the bottom of your blog post.
  4. Publish

Precalculus11-week17-5 things

Posted on by under Math 11

“Top 5 Things Learned in Precalculus 11”

REPASO UNIDAD 2 DE LENGUA Y MATES | 5º EP. SEK-Alborán

1. I learned this semester in precalculus 11 that even if I spend 20 minutes a day to study and review it helps me remember the steps. It helps because I am going over the homework again and making sure I am able to understand it for the next class.

2. Another thing I learned was that even if we move on to another unit there are many steps that could be brought with us for the next units. If I did not understand how to do a certain equation there would be one similar brought to the next unit and as I move on the more I understand.

3. As a learner I found it easier to have a visual of the equation and someone teaching me how to do it step by step first then I would try it myself, this way helps me the best.

4. I learned that it is okay to not get the right answer at first, but if you give up on the first try you will never succeed in learning how to actually do it. It takes time and it takes lots of mistakes to end up with the right result.

5. In precalculus 11 I learned that math is hard but it is possible. Not everyone is good at it but if you study hard you will get the grade you deserve, don’t go for the grade that will make you just pass, get the grade you work hard for and deserve.

Precalculus11-week16-Sine law

Posted on by under Math 11, Uncategorized

Sine law. The sin law is a very useful tool for solving triangles.

The sine law works for mostly every triangle and the equation for it is: \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}.

This means that when side a is divided by the sine of angle A, it is equal to the side b divided by the sine of angle B, which is equal to the side c divided by the sine of angle C.

Right Triangles and Trigonometry: Law of Sines and Law of Cosines

Say you had to calculate angle A, which is across from 8cm in this picture.

Remember the sine laws. \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}. in this question we are going to ignore sin C as it will not be needed.

  1. First put in the values that we know: Sin110°/61=sinY/37
  2. we put the degree of x on top and divided by 61 which is the length across. Then we input sinY because this is the angle we are looking for, underneath we divided it by 37 as it is the length across.
  3. we start by cross multiplying 37, now the equation should look like: 37sin110°/61=sinY
  4. apply this equation into your calculator, make sure to use inverse sine then apple equation.
  5. The answer you should get is Y=34.75°, since this is an angle round it to 35°.

 

 

week13-precalculus11-Multiplying and dividing rational expressions

Posted on by under Math 11

Multiplying and dividing rational expressions

A variable in the denominator position of a fraction cannot equal zero because it would not make sense for a number to be divided by zero. We must add restrictions so that the variable does not equal zero.

  1. Say you wanted to simplify \frac{2}{n} divided by \frac{4}{n}. We can cross multiply to simplify here. Multiply 2 and n & 4 and n. This will yield \frac{2n}{4n}. The two variables will equal one (cancel out) since one is in the numerator and one is in the denominator.
  2. We can then simplify \frac{2}{4}, which will then simplify to \frac{1}{2}. Since the variable n is in the denominator in the original expression, and we know that n cannot equal zero, we must state that in our answer.

Precalculus11-week12-Adding and subtracting rational expressions with monomial denominators

Posted on by under Math 11

Adding and subtracting rational expressions with monomial denominators.

  • Adding and subtracting fractions: when adding and subtracting fractions, the denominator must be the same. Brining back everything we know about like terms.

Say you wanted to simplify \frac{4}{a}-\frac{4}{3}. This equation may look hard but remember all that we know about fractions — remember, same denominator. To get the same denominator, we must multiply one side by 3 and one side by a. This will give us \frac{12}{3a}-\frac{2a}{3a}.

Now that both fractions have the same denominator, we can continue on with the expression. Notice that the two terms above do not have like terms — one is 2a and the other is 12. This means we cannot subtract them.Our final answer will end up being \frac{12-2a}{3a}.

  • Don’t forget the non-permissible values! For this expression, there is only one: a cannot equal 0.

 

Precalculus11-week11

Posted on by under Math 11

How to find the vertex, first is to put the equation into vertex form (completing the square if you were in general form, expanding factored form and then completing the square) because vertex form clearly displays where the vertex is in the equation.

The equation for vertex form is: a\left(x-p\right)^{2}+q. Look closely at p and q; that is where you are going to find the vertex.

Say you had the equation: y = 2\left(x-2\right)^{2}+5. When you look at the number inside the brackets, the sign will always be opposite to what it appears as inside the brackets. Positive nine remains the same, so we don’t need to change the sign next to the nine. Example: The vertex will be (2, 9).

Sometimes you will not have a value, so you will need to have more information to solve the equation in vertex form. If you had two points specified, let’s say (6,3), you would replace the x and y with these values and then solve the equation from there.

Precalculus11-week10-maximum and minimum

Posted on by under Math 11

Maximum and Minimum:

The vertex is the highest or lowest point of the graph, which is another way of saying the maximum and minimum. If the vertex of a parabola is the lowest point of the graph, then it is known as the minimum. It would look like a V shape. If the vertex of a parabola is the highest point of the graph, then it is known as the maximum. Would look like an upside down V.

The vertex is used to determine the coordinates of the point on the parabola’s axis of symmetry where it crosses it. By knowing if the parabola is maximum or minimum, we can see if the vertex is positive or if it is negative.

Original form of the quadratic equation: y = ax^{2}+bx+c. Now, we use this equation to find us the vertexes of the points on a certain graph.

You can change this equation into this to find the y-vertex: c-\frac{b^{2}}{4a}. While you can use the y-vertex equation, I prefer finding the x-vertex and plugging it back in to the equation to find the y value.

You can change this equation into this to find the x-vertex: -\frac{b}{2a}.

Week 9-Precalculus11-Factoring

Posted on by under Math 11

Factoring perfect squares

What is a perfect square?

A perfect square is a number that can be expressed as the product of an integer by itself or as the second exponent of an integer. For example, 25 is a perfect square because it is the product of integer 5 by itself, 5 × 5 = 25.

An example of factoring an equation:

  1. x²-16 first we divide the x in 2, next what times what equals 16
  2. (x-4)(x+4)
  3. now we check
  4. (x)(x)=x²     (-4)(4)=-16
  5. x²-16

 

 

Week7-Pre-calculus11-Factoring fractions

Posted on by under Math 11
  1. Today i am going to teach you how to factor fractions
  2. First thing i am going to do is give you a equation
  3. 5/4x² + 11/2x +2
  4. The first step is to change the 2 into a fraction so we put it over 1
  5. Now that your equation looks like  5/4x² + 11/2x +2/1 we want to have the same bottoms, so next we find a common denominator
  6. a number they all have in common is 4, so we times 11/2 by 2=22/4
  7. Next is we do the same to 2/1 we times it by 4= 8/4
  8. Now we change the fraction to 1/4 (5x²+22x+8), we then write 22x as a sum 20x+2x, we then factor out 5x from the expression and 2 from the expression
  9. 1/4(5x(x+4)+2(x+4)
  10. 1/4(x+4)+(5x+2), factor x+4 from the expression
  11. The answer is 1/4(x+4)(5X+2)

Week6-Precalculus11-Factoring Trinomials

Posted on by under Math 11, Uncategorized

First step of learning how to factor is to start with knowing how to change into factor form.

  1. If you get and equation like (2x + 1)(x+2) you start by multiplying the 2x and the x, next is the 2x and 2. After completing this begin to do the same with the one.
  2. (2x+1)(x+2)= 2x²+4x+x+2
  3. Next add all the same, 2x²+5x+2
  4. After completing on learning how to do this we are going to learn how to factor

Factoring a trinomial:

  1. If you get an equation like 8x²+2x-15
  2. Start by knowing that two number in the equation multiplied together is going to result in the pink number highlighted, next is the middle number highlighted in green, how to get it is by adding two numbers together.
  3. Start by writing it out, (_x+_)(_x-_)
  4. now what two numbers multiplied together equals 8, (2x+_)(4x-_)
  5. 3 and 5 equal to 15 so next, (2x+3)(4x-5)
  6. Now we check
  7. (2x+3)(4x-5), 8x²-10x+12x-15
  8. 8x²+x-15
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