Week9/solving A with factored form

Question: A graph passes through B(2,-5) and has x-intercepts -3 and 4

Before solving its good to analyse the question first. Passes through B(2,-5) represents x and y, well x intercepts represents the x intercepts. An equation that can use both of these clues is factored form since factored form has the x-intercepts in the equation.

Factored Form y= a(x-x1) (x-x2)

When plugging in the x intercepts from the equation you get  y= a(x+3) (x-4), this question may look solvable but it has more than one variables so you cannot solve it yet for A. Thats why you put the x and y into the equation. Now your left with -5= a(2+3) (2-4). From there you can now solve for a. (EXAMPLE BELOW)Now the equation is y= \frac{1}{2}(x+3) (x-4) now it is a complete equation and can be changed and graphed.

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