My Arithmetic Sequence

kaidenh2016 on September 11, 2018

Sequence: 31 + 35 + 39 + 43….. Find $t_{50}$ & $S_{50}$

$t_n$ = $t_1$ +(n-1)(d)

Answer/ $t_{50}$ = 31+ (50-1)(4)

= $t_{50}$ = 31+ (49)(4)

= $t_{50}$ = 31+ 196 = $t_{50}$ = 227

——-> $S_{50}$ = $\frac{50}{2}$ (31+227)

= $S_{50}$ = 25 (258) —> $S_{50}$ = 6450

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