Tag Archives: Absolutevalue

Pre Calculus Week 12:

This week in Pre-Calc 11 we started a new unit; Absolute Values and Reciprocal Functions. We continued off of the linear and quadratic functions we learned about, and how to graph these new kinds of functions. I will also show you how to right piecewise notation.

Reminder

linear function: y=mx+b

Quadratic: y= a(x-p)^2 + q

|Absolute value signs| : The distance away from zero, makes every number in between these lines positive.

When an absolute value symbol is added into an equation, it will force any part of the line or parabola that is in the bottom (negative) of the graph to flip and become positive. When this happens the point at where the line will have an immediate turning point also known as the point of inflection or as the critical point. This point usually has an x value and a y value of 0.

A few thing you will need to identify are:

  1. Point of Inflection (x intercept)
  2. y intercept
  3. Damain
  4. Range

Example: y= 4x +6 and y = |4x+6|

y=4x+6

Will turn into… when absolute value signs are added

Identify:

point of inflection:( -1.5, 0 )

y intercept: ( 0, 6 )

Domain: XER (because the graph goes on forever in each direction)

Range: y\underline{>} 0

Piecewise Notation

This a way to describe a function, and it has two parts.

  1. The first part, we write the original equation and when it is positive

 

 

 

 

 

This would be how to describe the positive part of the line

 

2.  The second part of the piecewise notation would be described by placing brackets around the equation and a negative in front to flip it to become positive 

The restriction helps to tell where the description occurs

3.  Now combine the two parts like…

This would be the complete way to write piecewise notation, and how to fully describe the function

Parabola

This would be very similar to a parabola

example: y = |1(x-5)^2 -1|

Would turn into…

 

Piecewise notation

The first part of the piecewise notation explains that any x value smaller than 4 will be positive and any number larger than 6 will also be positive.

The second part of the piecewise notation describes where the parabola would be negative, but it has been placed with the negative sign so it makes whatever is in the negative side positive. So any points between 4 and 6 would be negative, but the absolute value signs have made it.

positive.

 

This is how you would write piecewise notation as well as what a linear and quadratic function would look like on graphs when introduced with absolute value signs.

Week 3 Absolute Value and Simplifying Radical Expressions

This week in Pre Calculus 11, we learned what an absolute value of a real number was and how to simplify radical expressions.

Absolute Value of a Real Number : The principal square root of a square number. 

SOLUTION: The absolute value of a negative number is the opposite number, and the absolute value of a positive number and 0 are the same.

ex/    |-99| = 99         | 12 | = 12

This is because distance is always positive.

 

The long lines act as brackets but are not and it represents absolute value.

  • ex 1/         4 |15-20|
  •                     4 |-5|
  •                     4 (5)
  •                     = 20

 

  • ex 2/         |6 +(-10)| -|5-7|
  •                     |6-10| – | -2|
  •                     |-4| – |2|
  •                     4  –   2
  •                     = 2

 

Here is a video that really helped me learn and understand a little bit more about absolute value.

 

Radical Expressions

we also briefly reviewed radical expressions

Here a link to another post for radical expressions : http://myriverside.sd43.bc.ca/jessicap2015/2017/02/11/math-10-week-2/

ex/ \sqrt{25} =   5  and 3\sqrt[2]{5} = \sqrt{45}

 

Now to build off of radical expressions we are adding variables.

Solving

Step 1: Find perfect squares.

Step 2: Take them out / simplify

Step 3: Do the same with the variables (treat them like numbers)

ex/ \sqrt[2]{18x}

  • ex/ \sqrt[2]{18x^2}
  • \sqrt{9\cdot{x^2}\cdot2}
  • \sqrt{3\cdot3\cdot{x}\cdot{x}\cdot2}
  • 3x\sqrt[2]{2}

 

 

This is how to work with variables in Radical Expressions