Photography 12 Portfolio Reflection

  • I found the simplistic layout of my portfolio most successful as I feel it contrasts well with what I said in the Artist Statement. I purposely only had pictures due to this reason and to me it helps to just to focus on the photos. I also found my choice of photos and the order I put it in successful as well because I didn’t use all my photos but the transition for each photo in order I really focused on so that the book would have a nice flow; In tried to transition from light to dark and dark to light with my photo order.
  • Honestly I didn’t find any part of the portfolio unsuccessful I felt everything from the layout to the order of the photos, the photos I chose, the cover picture, and the transition from each photo really successful.
  • If I were to redo a project it would be the Copycat project just because I really wanted to do this project, but felt limited to what I could copy as I wasn’t able to go out and shoot. I get a lot of inspiration from the photographer I chose and would’ve love to try and recreate more exciting and dramatic photos outdoors.
  • Overall I felt this was a really good year of photography because I learned so much. Especially about Lightroom and Photoshop, and how to use them both together. I never used Lightroom before and now it’s my “go to” when editing. with Photoshop this year I really pushed myself to add certain details and try to make them look as natural as possible. I was able to do this in most of my projects and then could edit the final photo in Lightroom. I really like how I was able to learn about something I will be able to use in the future.

Quick Meal Nutrition Analysis

Today for breakfast I had two chocolate chip pancakes with maple syrup and strawberries. I also had a glass of milk with my pancakes. The pancakes themselves are a carbohydrate that provides your body with energy and the strawberries are a source of fibre. Fibre is important for digestion and also helps to make us feel fuller for a longer period of time. Carbohydrates and fibre are the macronutrients that were apart of my meal. With the pancakes and strawberries I had a glass of milk to go with it. Milk contains vitamin D and calcium that is a mineral which helps strengthen our bones and teeth.

Core Compentency

The Math Pre-calculus 12 Transformations unit has helped me improve my critical thinking because I have to analyze graphs and write down what is happening to each function. It has improved my creative thinking because I have to draw the graphs and now. know how to manipulate it where I could move all types of graphs up, down, left, or right. It has improved my communication skills because I verbalize what it happening to each function and once I verbalize I can then use replacement language to show what I am doing.

Week 16 – Pre-calculus 11

This week in Math 11 we started grade 11 trigonometry and we learned how to make a right triangle and from coordinates of a point that is given. With the right triangle we can find the the opposite and adjacent side, along with the hypotenuse and the reference angle. First we find our point on the graph and draw a diagonal line from the origin to the point, then from the point we draw a vertical line connecting it to the horizontal line or x-axis. then based on our coordinates given we will know the values of our vertical and horizontal lines but we will not know the value of our hypotenuse. We can figure out our hypotenuse by using Pythagoras theorem which is a^2 + b^2 = c^2. Once we know all the lengths we can figure out all of our ratios and then find our reference angle.

Example:

Point (6, 4)

we have our point and not we draw a line between the point and origin

Then draw a vertical line between the point and x-axis

now we start to see our right triangle

The points that were given to us in the beginning tell us the value of 2 of the sides on our triangle

From here we need to find the value of our hypotenuse

  • to do this we use a^2 + b^2 = c^2
  • our hypotenuse is our c^2
  • and 6 is “a” and 4 is “b”
  • a^2 + b^2 = c^2
  • 6^2 + 4^2 = c^2
  • 36 + 16 = c^2
  • 52 = c^2
  • \sqrt{52} = \sqrt{c^2}
  • c = \sqrt{52}

Now that we know the hypotenuse we can now find out all our ratios for Sin, Cos, and Tan, along with our reference angle

based off where are reference angle is

  • For Sin it is \frac{O}{H}, where “4” is our opposite and “\sqrt{52}” is our hypotenuse.
  • For Cos it is \frac{A}{H}, where “6” is our adjacent and “\sqrt{52}” is our hypotenuse.
  • For Tan it is \frac{O}{A}, where “4” is our opposite and “6” is our adjacent

So our ratios would be

  • Sin \theta = \frac{4}{\sqrt {52}}
  • we don’t like having a square root on the bottom so what we can do is rationalise the denominator to make our answer look better
  • Sin \theta = \frac{4}{\sqrt {52}} x \frac{\sqrt {52}}{\sqrt {52}}
  • Sin \theta = \frac{4\sqrt{52}}{52}
  • We would do this for all ratios to make them look better
  • Cos \theta = \frac{6\sqrt{52}}{52}
  • Tan \theta = \frac{4}{6}

Now that we have all of our ratios we can solve one of them with a calculator to find our reference angle and we would that number to the nearest degree.

  • Tan \theta = \frac{4}{6}
  • \theta = (tan^-1)(0.667)
  • \theta = 34°
  • and this is our reference angle

Week 9 – Precalculus 11

This week in precalc 11 we learned about how to find maximum values and revenue using quadratic functions, we can also find different variables depending on the word problem for example if there’s a question about area then the question may also ask for the length and width and we have to use the quadratic function to solve for the side lengths along with the maximum values.

Example: A company can sell 56 phones, each one being sold for $300. For every $30 the price increases, the number of phones sold lower by 3. What is the maximum revenue that the company can make by selling the phones?

The formula we use for revenue is: (price)(# of sales)

so knowing this lets see what we know

  • we have 60 phones
  • each one is sold for $300
  • the price can increase by $30
  • But then the number of phones drops by 3
  • Were trying to find the maximum value

know we need to use a variable to find out our maximum revenue

The variables will be how many phones we decrease by and how much we increase the price

So lets plug in the number we know into the formula

(300 + 30x)(60 – 3x)

Now we can solve for the variables by completing the square but first we distribute

(300 + 30x)(60 – 3x)

18,000 – 900x + 1,800x – 90x^2

-90x^2 + 600x + 15,000

Now we can complete the square and find our vertex which will give us our “x” value and maximum revenue.

\frac{-90x^2}{-90} +\frac{900x}{-90} + 18,000

-90(x^2 – 10 + 25 – 25) + 18,000

-90(x - 5)^2 + 18,000

Vertex is : (5, 18,000)

Our “5” shows our value for “x” and the 18,000 shows our maximum value but because in this question it’s asking for revenue it is our maximum revenue.

Sometimes a question may ask, “which price for a phone will maximise the revenue?”

and what you do is go back to our formula with the numbers

(300 + 30x)(60 – 3x)

and in this case the “(300 + 30x)” talks about the price for a single phone so we plug in our “x” value we got from our vertex and solve to find our the price of one phone that would maximise the revenue.

(300 + 30x)

(300 + 30(5))

(300 + 150) = 450

so this means the price of $450 for one phone will maximise the revenue in this question.