## Week 18- Five things I learned in Pre-cal 11

• Forms of the quadratic equations

What I have learned:

Multiple forms of the Quadratic functions, such as Standard form, Vertex form…

with each form, one can find different information about the equation and its graph. Such as in vertex form you can find the vertex… with the Standard form you can find the roots, then the axis of symmetry then the vertex with this information.

Why is it important:

This is once again the setting stone for higher math and knowing the different form of the Quadratic Functions are very important.

## – Trigonometry

• Sine/Cosine Law

What I have learned:

• Sine and Cosine Law are two additional ways that I have learned this year to determine an angle or a side.
• Sine law Sin A/a=Sin B/b= Sin C/c
• Cosine Law: Why it is important:

Trig will be a very important part of pre-cal 12 and this will be the foundation of that.

## – Reciprocal Functions:

• Graph Reciprocal Functions:

What I have learned:

• A reciprocal of a number is the opposite of the number.
• Graphing Reciprocal Function is how one graph Reciprocal Functions.
• If you known fraction then you should know if 1/x and x<1, the number will become greater, and vice versa if x>1, the number will become smaller. In graphing, this will result in some very interesting observations. In the above graph that is a  linear equation x+6=y

And when we get the reciprocal 1/(x+6)=y of the equation the graph looks like this: • To draw this you find the roots of the equation or root in this case, to determine the vertical asymptote, the horizontal asymptote will be 0 until pre-cal 12. The asymptote is a barrel and it keeps the function to one side of it.
• And then you determine the invariant points, Because when 1and -1 inverse their yield doesn’t change, so when y=1,-1 those x coordinates are called invariant points.
• At last, we can basically draw the function just follow close to the asymptote in the zone where the original function has been and cross over the invariant points.

Why it’s important:

1. Graphing will be a huge part of pre-cal 12 and I believe that reciprocal functions will be important then as well.

# Learning Habits:

## – Learning Habits:

• Build an extensive note-taking system.

What I have learned and will do next year:

• This year, I had a very pool system of taking notes. I wrote all my notes in the textbook, wherever there is an empty space… And with an extremely faint pencil that rubs away in a week… And eventually consequently resulted in my not ideal test grades as when I try to go back and find my notes, there isn’t anything there to be found and review…
• This summer I  am getting private tutoring on Pre-cal and Cal and Chem in China, I will start using my extensive note taking system then… I will use a Rhodia notebook for each subject, and reserve space for planning my learning, working ahead, chapter notes and review. And I will write with a  Fountain pen…

Why it’s important:

• Grade 12 is an extremely important year, no more messing around if I want my feature… And with the area that I’m interested in Math is extremely important… In order to keep my GPA goodish, I need to make sure I get good marks on my math in Grade 12 and note taking will help me with that along with studying ahead.

## – Learning Habits Volume 2:

• Better utilization of test time.

What I have learned and will do next year:

•  This year, I did not finish many tests… What a shame, as I got all the questions I did finish right but couldn’t finish the test and let those A slipped away… I must change that in Grade 12 and I think I know how… I couldn’t finish the test is due to my over excessive examination of the questions, crazy imagination and OCD like answer checking while doing the test… I will force myself to only focus on the test questions and do all those crazy checkings after the test is finished…

Why it’s important:

• Grade 12 is an extremely important year, I need my grades… Not that much messing around is allowed in Grade 12…

## Week 17- Trigonometry

This week in Pre-cal 11 we learned Trigonometry again, the difference in comparison to the pervious knowledge we learned in grade 10 are, now SOHCAHTOA, works in all 360 degrees and we learned two new laws: the sine and cosine law which comes in handy when there isn’t enough information for SOHCAHTOA.

And this is how trig ratio is possible for all angles<360. I was introduced to this circle, with have 4 quadrants, basically, the x-axis of it is the principal axis and there are two angles, one is the rotation angle, the angle of that is measured from the X axis in the top right quadrant, the quadrant one, and the angle between that and the X-axis is the reference angle and the reference angle have the same trig ratio as the rotation angle, but it might be negative. And how do you determine if a rotation angle in a certain quadrant is negative with its trig ratio, there is something called the CAST rule, with that you can easily determine if your trig ratio is positive or negative.  This is the Cosine law, it can determine an angle with the length of the two sides created it known, vice versa you can find the any of the side lengths with the angle and when the other side is known as well. The is the Sine Law, it can determine any angle or sides in a triangle with two sets of side and the angle opposite of it, using the ratio one can cross multiply and solve to find any one of these variables with other three. ## Week16- Solving Rational Expression

This week we finished the rational expression unit.

And this week we learned how to implement the skill of solving Rational Expressions into the real world problems.

EX: Boat A is moving up a stream, and boat B is moving down the same stream, it took Boat A 2 hours to cover 15km and Boat B took only one hour, the current is 3km/h, what’s the speed of the boat in still water?

Set Boat A, B speed as Xkm/h in still water, therefore Boat A will move at x-3km/h and Boat B will move at x+3km/h.

15/x-3=2, 2(x-3)=15,2x-6=15,2x=21,x=21/2,x=10.5km/h

## Week15- solving rational equations

Last week we learned how to simplify a rational expression, and this week we explored how to solve a rational equation.

The difference between equation and expression is pretty straightforward, the expression does not have an equal sign, it only expresses its meaning. An equation on the other hand obviously have an equal sign, and our intent will be the solution the unknown instead of just simply simplifying it.

There are two common ways to solve a rational equation.

1: Cross multiplication, only works when there is only one fraction on each side of the equal sign.

EX: In this case, I multiplied(q-2)by5, and (q+4)by3.

2. Use a common denominator, and solve.

EX: The common denominator, in this case, is 6z.

## Week14- Rational Expressions

Last week we learned about Rational Expression, aka all real values of the variable except for those values that make the denominator zero. AKA2: In x/y, how to make sure y is not 0.

In particular, we learned about the how to make sure the denominator not equal 0 with something called non-permissible(the numbers one can’t use, or the denominator will equal zero and the expression will no longer be Rational.)

EX: Outside of non-permissible values, we also learned how to simplify and/or multiple, divide Rational Expressions. But due to the fact, a Rational Expression or any real number, in this case, is a fraction, all to be done is to follow the law of dividing and multiplying of the fractions. AKA: why diving, multiply by it’s reciprocal. and why multiplying just multiply the numerator with the numerator and the denominator and denominator, but just keep in mind that in any rational expression the denominator can’t be 0, so there may be non-permissible as well. And as it’s an expression, all you can do is to simplify it.

In a fraction, when denominator equals the numerator, the number equals 1. EX: 8/8=1

EX:

So in an equation such as 3x.8(x-3)/2(x-3).9x^2. It might be helpful to use factoring to find the common thing that can cancel out to 1, like how (x-3) and 3x in this case. So after finding the common terms. they will just cancel out to 1, and in this case, 3x and 9x^2,(x-3)and (x-3) cancels out. and leaves you with 8/2.3x=8/6x=4/3x and don’t forget about the non-permissible, and remember you have to find them in the original equation, as they will be lost when you simplify the equation. In this case(x-3)can’t be 0, therefore x not equal 3, and 9x^2 can’t be 0, therefore x can’t equal 0.

## Week 13- graphing linear reciprocal functions

a reciprocal of a number is the opposite of the number, or using the cool math language is 1/the number.

If you known fraction then you should know if 1/x and x<1, the number will become greater, and vice versa if x>1, the number will become smaller.

So in graphing, this will result in some very interesting observations.

Let’s use this linear function as an example, x+6=y. when you invert this function to 1/x+6=y, magical things will happen, ex:1/6+6=1/12, whereas the original function will yield 12. But this sort of magic has three exceptions,  1,-1 and o, as their inverse equals themselves, expect 0, as 0 can’t be divided by. With this information in mind, we will be able to determine how a linear inverse function.

Because when 1and -1 inverse their yield doesn’t change, so when y=1,-1 those x coordinates are called invariant points.

The second step in solving is to draw something called vertical asymptote, as we are in pre-cal 11 the horizontal asymptote will be 0, the asymptote is like a great wall that keeps the number on their own space because 0 can’t be divided. the vertical asymptote will always be the roots or the x-intercept.

With the asymptote and invariant points, we can basically draw the function just follow close to the asymptote in the zone where the original function has been and cross over the invariant points, you have successfully drawn yourself an inverse linear function. ## Week 12- graphing linear absolute value function

An Absolute value (||) means whatever inside is going to be positive, when we put a linear function within ||, it becomes an absolute value linear function.

The graph of it will change, as we know, a linear function is a straight line, either having a 0 slope or / positive slope or \ slope.

When graphing an absolute value linear function, if the slope is not 0, the line will bounce back up in the opposite direction of the original function at x-intercept.

Why is that?

Let me show you an example:

2x+4=y, a simple straight line with a slope of 2, and y-intercept of 4. But magic happens when you put||on to the function. As the output of an absolute value cannot be negative,  y, in this case, will also have to positive.  But with our previous graph of the original equation, the Y clearly dipped under 0.

Let’s see what happens if we put an x value that would make y<0 into the absolute value equation.  |2x(-4)+4|=4, the Line reflected up, from this example we can learn that when graphing a linear absolute value function, all you need to do is find the x-intercept of the original line and draw a reflected line from the original root.

## Week 11- graphing linear inequality with two variables

In previous grades, we learned about linear equations and inequalities with one and two variables, now we learn how to solve them graphically.

To graph a linear inequality with two variables we firstly rearrange it to y-intercept form in order to graph it.

EX: 2y+6<4x,

With y-intercept form of the equation, we are able to graph a line just how we did in grade 9. The difference is in an equality the equation represent the values on the line and inequality represent a whole area.

A line will divide the graph into two zones, we just need to determine which zone to shade(it represent a range of value)

The most accurate way of determining such things is by trial and error,

we would take two test coordinates from each section of the graph and plug it into the equation, if the equation is true then the side with the coordinates will be shaded.

EX: (0,0) , (-5,5)

2(0)+6<4(0) 6 is not less than 4, therefore the otherside will be shaded.

One last thing you have to do before you submit your answer is to determine whether you should use a solid line or dotted line if the sign involves = sign, you use a solid line.(In this case it’a dotted line due to the fact that it’s only a < sign). ## Week 9- Analyzing general form of quadratic equation

In week 9 of pre-cal 11 We learned how to analyze the general form of quadratic equation along with many things.

With analyzing, I mean you factor the equation if it’s factorable. And apply the knowledge I learned from last unit to find the two or 1 roots, and using logical thinking such as the axis of symmetry must have the same distance on the x axis to both roots and etc to find more information without changing the equation into standard form.

## Week 8 – Graphing Quadratic Equations

In week 8 of pre-cal 11, we learned how to graph quadratic equations with the general form and the standard form.

a $x^2$+bx+c, is the general form of the equation, with this form the equation we can find limited information comes to graphing; we can determine the direction and the compression ratio of the graph from a, and y-intercept from c.

But we can easily change this equation to standard form by completing the square; $y=a(x-p)^2+q$ from this form of the equation we can determine the position of the vertex with q being the y-axis(+ going up,- going down), p being the x-axis(- going right, +going left) and the direction of opening and the compression ratio of the graph by looking at a,( the ratio of the graph will be congruent to a $x^2$=y, a determines the direction of the graph( if negative a, facing down, if postive a opens up).