Week 6 – Math 11 – Solving Trinomials

In this week we learned how to balance trinomials, to do this we use this formula,

$X=$ $\frac{-B \sqrt{(b)^{2}-4(a)(c)}}{2(a)}$

so lets say we have this as our equation,
$3X^{2} + 8X + 24=0$

first we must identify A, B and C,
$3$ is A
$8$ is B
$24$ is C

So using these values we must replace them in the spots of the formula with the matching letters,
$X=$ $\frac{-8 \sqrt{(8)^{2}-4(3)(24)}}{2(3)}$

Now we will evaluate the equation,
$X=$ $\frac{-8 \sqrt{64-288}}{6}$
then,
$X=$ $\frac{-8 \sqrt{-224}}{6}$

after you get to this point we must find a common factor to divide everything with,
$X=$ $\frac{-8 \sqrt{-224}}{6}$ $/$ $\frac{2}{2}$

Giving us,
$X=$ $\frac{-4 \sqrt{-56}}{3}$

simplified again,
$X=$ $\frac{-4 -2\sqrt{14}}{3}$

and that’s the final answer!

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