# Grade 11

# Week 4- Math 11

In week 4 we have learned 2.3 adding and subtracting Radical Expressions and Multiplying and Dividing Radical Expressions. Adding and subtracting radical expressions sound hard but they are easy. Step 1: Simplify each radical. Step 2: add or subtract the same number inside the Root symbol(√), for example, 4√a, 3√a. This two example the number inside the Root is same so if they add together will be 7√a, if they subtracting will be √a. Multiplying Radical Expressions, step 1: Multiplying the number with another number. Step 2: simplify if possible. For example, √6(√6-√2) = √36- 2√6 = 6 – 2√6.

# Week 3 in Math 11

Week 3 we just get into a new unit about absolute value and radicals, and we learned absolute Value of a real number and simplifying radical expressions. Also we did a test of first unit Sequences and series. The absolute value of a real number a is denoted by. a. and it is the distance from a to the origin 0 on the number line. The absolute value is always positive. Simplifying radical expressions step: Step 1: Find the prime factorization of the number inside the radical. Step 1: Find the prime factorization of the number inside the radical. Step 2: Determine the index of the radical. In this case, the index is two because it is a square root, which means we need two of a kind. Step 3: Move each group of numbers or variables from inside the radical to outside the radical. In this case, the pair of 2’s and 3’s moved outside the radical. Step 4: Simplify the expressions both inside and outside the radical by multiplying.

# Week 2 in Math 11

This week is the second week in math 11. We learned Geometric Sequences and Geometric Series. A Geometric Sequence is a sequence in which the ratio of the common terms is equal and a Geometric Series is a series with a constant ratio between successive terms. For example, the series. Also, we learned how to input code in Edblogs for example, .

# Week 1 – My Arithmetic Sequence

S=+ …..

= 20

Common difference: + 10

What’s the and What’s the

*

*

*

Solution:

*

*

*

=+(n-1)d

=20+(250-1)10=2510

*

*

*

=20

=20+20+(10)=50

=20+20+(10)+20+(10)+(10)=90

=20+20+(10)+20+(10)+(10)+20+(10)+(10)+(10)=140

*

*

*

= 20+20+(10)+20+(10)+(10)+20+(10)+(10)+(10)+***

= x (20 + 510)

= x 530

=56250

In conclusion, = 2510 and = 56250