April 28

Week9 math 10

This week in learns how to factor difference of squares.

Difference of squares is when when you have trinomial that end in a negative and every number has a square rout. You if you do have a difference of squares you should be able to chage your trinomial into a binomial. You would be able to do this the prossese of elimination showen in the ample below.


This is considered because both of thes numbers have a square root and can be simplified.

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April 27

Week 10 math 10

This week we learnt how to factor simple trinomials and how the factor the GCF of trinomials.

Factoring simple trinomials:

To factor simple trinomials you need a trinomial that has the right pattern which I X squared + or – x + or – #. To factor this you must find two numbers that can add to the number in front of the X and can multiply the lone number.


Factoring the GCF:

To factore the GCF you must find the greatest common factor. Which pretty much means you must find the highest number possible that each of these numbers can be divided by.

As you can see in this example I chose 5 as my greatest common factor.

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April 27

Week 8 math 10

This week in math we learnt how to simplify and expand polynomials.

First if you were looking to simplify a polynomial you would need to eliminate the brackets then group like terms together. After you’ve done so depending on weather or not the sing in front if the number is a positive or negative you will to either add or subtract the number from the like terms.

Secondly if you were looking to expaned a polynomial you would need to distribut through out it. To do this you must take the nuber out I front of the brackets and multiply it by each number inside the brackets.

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April 5

Math 10 week 7

  1. In this first equation we had to use SIN, because we have the hypotenuse and we are trying to find the opposite side. To use this equation we need a minimum of three pieces of information( where the reference angle is, where the 90 degree angle, and how long one of the sides are). After labelling all the sides you must find out which calculation to use in this case we are using SIN and the equation is ( Sin 31)=x/46
  2. In this second equation i used COSIN because we new all the information that we needed. We had the length of the opposite and we were trying to find the length of the hypotenuse and we know what the reference angle is. After labeling all the sides, we use the equation (COSIN 23)= 32/x
  3. In the third triangle wwe had to find the reference angle which is alot different type of formula the trying to find one of the sides of the triangle. In this case we still need three peices of information but it’s a bit different in the way that we dont yet have the reference angle. So by finding it we can then find the rest of the measurements of the tryangle. Thr equation that we use is (23/29) tan-.
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