Math 10 Week 15

This week in math I’ve learned how to use the slope formula to calculate the slope of a line segment.

This is how you do it:

ex: C(36,-41) and D(-20,-27)

to make the equation, you do rise1 – rise2 over run1 – run2. This is where C(run1,rise1) and D(run2,rise2). You start by subtracting -41 from -27 which equals -14, and then subtract 36 from -20 which equals 56. The product should be -14/56 which could be reduced to -2/8 and then to -1/4

 

Math 10 Week 14

This week in math I learned how to find the length of a line segment using points.

example: A(2,7) to B(5,7)

For this, I know that the points are ordered (x,y), so the y value does not change. The x value however, is not the same in both points.
For point A, x=2, and for point B, x=5. The length of the line is 3.

A more complex example would be; P(-6,6), Q(-6,-10), and R(8,-10).

this is what it would look like on a grid.

If you were going to have to find the distance from P to R, you will need to fine the other 2 lines, Q to R and P to Q in order to find the distance from P to R.
You can get PQ and QR from looking at the graph, with the length of PQ being 16 and QR being 14. Next, to find the distance from P to R you would use Pythagoras theorem. 16 squared is 256, and 14 squared is 196. 256+196=452. the square root of 452 is 21.260. But if the question is asking for an exact value that wont work. so you will need to factor 452.

 

that is what PR would equal as an EXACT value.

Math 10 Week 11

LCM (lowest common multiple) and GCF (greatest common factor) are very important for deciphering some equations.

The GCF is the greatest factor that divides two numbers. to factor this polinomial, you would need the GCF:

The greatest common factor would be 2x.

 

The LCM is the smallest integer that is evenly divisible by both a and b. For example,LCM (2,3) = 6 and LCM (6,10) = 30.

the LCM is 75n to the power of 4

Math 10 Week 7 Updated

How to solve for sin, cos and tan on a right triangle:

SOHCAHTOA is helpful to memorise the equations for sin, cos and tan.

SOH is sin= opposite/hypotenuse

CAH is cos= adjasent/hypotenuse

TOA is tan= opposite/adjasent

the hypotenuse is found diagonal from the 90 degrees point, the adjacent side is found next to the angle point, and the opposite side is found across from the angle.

here are some examples of how to solve missing parts of a triangle:

Math 10 Week5

This week in math I have learned how to convert different measurements in the Imperial System: Example: 0.04mm to meters.

using this scale, every line up you divide by 10 and every line down you multiply by 10.

 

 

 

 

So on the scale you go up 3 steps, from mm to meters, dividing by 10 each step. so in total. so you would divide 0.04 by 1000, which would equal 0.00004, or 4 x 10 to the -5