Week 6 – Solving quadratic equations by factoring

When you have the equation ax^2+bx+c=0 you can solve for x by factoring this equation

Ex. x^2+8x=-15

=x^2+8x+15=0

Now that we have the factorable equation into the form we want, we are now able to factor it into two binomials so that when we multiply them it equals ar equation.

(x+3)(x+5)=0

We can see now that x has two possible answers because when one of the binomials equals zero than we still have 0 on the other side since n*0=0.  So, we know that our two possible values for x are -3 and -5 because when we add them back into the equation, we get 0.

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