week 7- Solving for Right triangles

This week I learned how to solve for a right triangle. To do so I learned to do the following steps…

To solve for a right triangle, depending on the information given you can use the Pythagorean Theorem and/or trigonometry to solve the triangle.

When you have a right triangle (one angle is exactly 90 degrees) you can use trigonometry to solve the triangle using the sin cos or tan function. These functions also are known as soh, cah, toa.

Using the information given for the triangle above, we know that we have the hypotenuse and the opposite side measurements of the triangle. So we can use sin, because sin equals the opposite side length of the triangle over the hypotenuse side length of the triangle.

After solving the equation for this right triangle we would then type the equation into the calculator using the proper function to get the correct answer.

 

 

 

week 8- Using distributive property

This week I learned how to use distributive properties while multiplying a polynomial by a monomial. To do this I learned to do the following steps…

Ex. -5(2x² + x – 6)

= -10x² – 5x + 30

We then distribute the the -5 into the brackets. In this process we expanded the polynomial expressions by using the distributive property a(b + c) = ab + ac and the exponent rule xᵃ × xᵇ = xᵃ ⁺ ᵇ

week 11- Factoring a Polynomial by using the greatest common factor

This week I learned to Factor a polynomial by removing the greatest common factor. To factor a polynomial by using the greatest common factor I learned to do the following steps…

Ex. 8x²y² + 20xy³

Step #1: Find the greatest common factor between the two terms.

4xy²

Step #2: Factor the greatest common factor from the term by dividing it out of the two terms.

8x²y² ÷ 4xy²

= 2x

20xy² ÷ 4xy²

= 5y

Step #3: Put the two quotients together in brackets and keep the greatest common factor outside the brackets.

4xy²(2x + 5y)

The greatest common factor 4xy² has now been removed from each term, and the polynomial has been factored.