Welcome to one of my PE 10 self assessments.
Welcome to my electric house project blog post! In this project we had to make a house with four rooms and input a circuit into each room. Below are individual project questions, a circuit diagram for all the rooms, pictures of the house and a core competency reflection sheet.
- You have three lights bulbs. All have the same intensity when lit. Explain how you can prove to a classmate that they are connected in series by unscrewing one light bulb. Support your answer.
- A series circuit has all the electrons running through each load in the circuit, but due to this fact, unscrewing one light bulb will cause the circuit to open which means all the other loads will turn off.
- You have three light bulbs. All have the same intensity when lit. Explain how you can prove to a classmate that they are connected in parallel by unscrewing one light bulb.
- A parallel circuit allows the electrons to choose which path they travel. Which can allow multiple loads to be powered on or off in the same circuit. You can prove that a circuit is parallel if you unscrew a light bulb and the rest of the bulbs remain powered.
- You have three light bulbs. Two are connected in parallel. This parallel combination is connected in series with the third light bulb. Describe the relative intensity of each bulb. Support your answer.
- The two parallel bulbs will be less intense then the series bulb. This is due to the fact that the electrons have to choose whether to go to either of the parallel bulbs but will have to go through the series bulb. Which means that you could assume that the parallel bulbs will have around half the intensity of the series bulb.
- In question number three, describe the relative intensities of the two remaining lit bulbs if one of the bulbs in parallel was unscrewed. Support your answer.
- If you were to unscrew one of the parallel bulbs then that bulb will likely become an open area in the circuit. I imagine that electrons will still either go to the remaining bulb and then to the series bulb or they will go the other direction and leave to circuit. So I believe that the intensities of the two remaining bulbs will be the same but with the same intensity of the first bulb. Unless if you close the circuit after removing a bulb which would cause the first bulb to have half the intensity of the second bulb in the circuit.