Substitution VS. Elimination Both of these methods are used algebraicly for finding solutions of 2 equations of lines. Step 1: Pick ONE equation & re-arrange so it is x=____ or y=____ Step 2: Substitute this into the OTHER equation (use brackets!) Step 3: Solve equation Step 4: Substitue the number just found back into the […]
Tag: Burtonmath10
Week 15- Math 10
This week, we explored equations and patterns of lines on a graph. Hint: parallel lines = same (m1 = m2) perpendicular lines = reciprocals of eachother (m1 x m2 = -1)* -The 2 equations we can use to find lines given a few clues are: y = mx + b OR m = y-y / x-x […]
Week 11- Math 10
Video Concept: Entire Radicals VS. Mixed Radicals
Week 10- Math 10
Polynomials Something that stumped me this week was figuring with “method” to use for each polynomial question. I was mixing up product and sum, GCF, and double distributing. During the lesson, we came up with questions as a “flow chart” to decipher which method to use: If you can say yes to any of the […]
Patterns in Polynomials
Patterns can be found in polynomials using number equations or algebra tiles….. 1) Multiplying 2 Binomials- If we have, ex. (x+2) (x+3) , we can find all 3 terms without doing double distributive: -First term: multiply the first 2 terms together, = […]
Week 9- Math 10
Factoring Polynomials One concept that stumped me at first this week was finding the GCF while factoring polynomials. *Side Note: factoring polynomials = the opposite of multiplying polynomials, so we put the brackets back in the question! In this question during the lesson, we were asked to find the factored form of: 12ab + After I […]
Week 8- Math 10
One question that stumped me this week was during our first lesson of multiplying polynomials. (2x -4) (x -3) I wasn’t sure how to distrubute it as both terms are within brackets. I then realized that we can still distribute the first term to the second term, just in 2 separate parts. (Photo below) This made […]
Week 7- Math 10
One question that stumped me this week was a word problem based on finding a missing angle in the equation. At first, I thought that the 400 m would be thy hypotenuse. When I was informed that it was the horizantal of the mine shaft (the ground) , then I figured out that I needed to use […]
Week 6- Math 10
One concept that stumped me this week was using trig to find missing side lengths. By using SOH CAH TOA and the following steps it is simple to solve. 1) Find the reference angle 2) Lable the sides 3) Find the ratio (SOH CAH TOA) 4) Plug into the equation 5) Solve! An example we […]
Week 5- Math 10
One concept that stumped me this week was in the new measurement unit: Unit Analysis When we were given the first question- 50 km/hr = _____ m/s I wasn’t sure what would be the best way to solve this without using the number line. During the lesson, we started with what we knew about km, hr, […]