My arithmetic sequence

$t_1$ = 3, $t_2$ = 10, $t_3$ = 17, $t_4$ = 24, $t_5$ = 31.

So 3, 10, 17, 24, 31…

$t_{50}$?   $S_{50}$?

what I would do first is find out what is $t_{50}$.

$t_n$=$t_1$+(n-1)d

$t_{50}$=3+49(7)

$t_{50}$=3+343

$t_{50}$=346

Now I need to find $S_50$.

$S_n$=$\frac{n}{2}$($t_1$+$t_{50}$)

$S_{50}$=$\frac{50}{2}$(3+346)

$S_{50}$=25(349)

$S_{50}$=8725

So $t_{50}$=346 and $S_{50}$=8725.