Blackout Poem- I Know Why the Caged Bird Sings

Blackout Poem

            For my black poem, I did “I Know Why the Caged Bird Sings,” by Maya Angelou. The poem’s denotative meaning, is that there is a bird that’s trapped inside of a cage, and sees other birds and wishes it had their freedom. The connotative meaning of this poem, is that black Americans had no freedom, and that they were being discriminated. The speaker basically describes how life was for the African Americans during this time, they felt like they were trapped inside of a jail, because they had so many restrictions. The caged bird, describes the free bird as a dream, every time the caged bird sees the free bird soar through the sky, it wishes that it could be just like it one day. During this time, the African Americans were always treated horribly compared to Caucasian people, making the African Americans feel degraded, and all they can do is try and use their voice to make a difference; because the bird and the African Americans had nothing but their voices to use. The theme of this poem is that, even if you’re trapped your voice and opinion cannot be oppressed. This poem is significant, because it has an allegorical reference, to the time where African Americans had no freedom and rights. This poem portrays the voice of African Americans, and that their voice matters, nothing can stop them from using it even if they’re trapped in a cage. In the third stanza, lines 16 and 18, there’s end rhyme with the words, trill and still. There’s personification, because she describes the tree sighing, and we know that trees can’t sigh. There’s symbols, when describing the free bird and the caged bird, “A free bird leaps on the back of the wind, and dares to claim the sky.” The caged bird, “But the bird that stalks down his narrow cage can seldom see through his bars of rage. The speaker is trying to tell us that these are human’s and not birds, because this is not how birds think.


Week 15 Math blog

This week in math, we learned how to multiply and divide binomials. The first step is always to factor if possible, we always need to take a look at what we’re doing; either multiplication or dividing. From previous math, we know that if it’s dividing then we need to reciprocate the fraction. The next step is to simplify all like terms, you always need to find what X can’t equal to, because the denominator cannot equal 0.

In the examples below, i forgot my non-permissible values, for the first one it’s b cannot equal 0, and same for the second one, except B and A cannot=0

My first step was to examine what equation i was dealing with, and i applied all the steps above to help me solve the solution


Week 14 Blog post

This week in math, we learning how to simplify radical expressions. If the top the same term as the bottom they can cancel each other out. Our first step is to simplify the expression and then you find what the variable cannot equal to, sometimes there are more than 1 solution. In the example below:

I first found what the X value cannot equal to, so it was 0,9. Next i found all like terms and cancelled each other out X, (X-3). This left me with 24/18x which i could then simplify to 4/3x.

Week 13 Blog Post

This week is math, we learned how to graph absolute values, meaning the graph cannot cross the X axis to become negative. How this works, is the point it normally crosses to the negative side, reflects going the opposite direction using the same pattern, let’s say we were using 3x+2, when it reaches the point where it’s supposed to cross it goes up 3 then to the other way 2. If we were going up 3 over 2 to the right the reflected side would be up 3 over 2 to the left. We also learned how to do this with parabolas but instead of one line, it will be the vertex that will be reflected, the same rules also apply, the X intercept is like an invisible wall which will not let the line/ parabola cross to become a negative.

In the first picture, this graph represents the graph of x2+3x-5 and |x2+3x-5|. The green line represents the parabola if it were to be just graphed, no absolute values; we can see that it crosses the X intercept making it negative. In the orange lines, we can see the vertex is reflected, because the invisible wall reflected it back to a positive, having the same vertex but positive.

In the second picture, the orange line represents the normal value where it goes into negative 3x+2, and the blue line represents the absolute value version, where it’s reflected, which the equation is|3x+2|. This represents the absolute value, where it reflects right before it crosses the X intercept using the same pattern as the normal version but going up 3 to the left 2…