Week 3 in Precalc 11

This week in math 11 we learned about absolute values. A absolute value is always positive so if you have |-6| then your answer would be 6.

In this example I have the equation $\frac {|2 - (-8)|} {|3| - |-2|}$ so we know that 2 – (-8) would turn into 2 + 8 so our numerator would be 10. Then we would have |3| – |-2| since -2 is an absolute value it is changed into 2. then we have 3 – 2 = 1.

so our fraction is $\frac {10} {1}$ = 10

Another example is | $x^2$ + 6x – 5|, x = 2

So if X = 2 then we know $2^2$ = 4 and 6 x 2 = 12

|4 + 12 – 5|

4+ 12 = 16

16 – 5 = 11

= 11

Category: Grade 11, Math 11 | LEAVE A COMMENT

September 16

Week 2 in Precalc 11

This week in Math 11 we learned how to solve arithmetic sequences, to solve a arithmetic sequence you need to remember a simple equation : tn = a + (n – 1) d.

So if we have the sequence 7, 10, 13, 16… then d (common difference) would be 3. If we wanted to find term 8 we would need to use the equation. So it would be $t_8$ = 7 + (8 – 1) 3. which would be $t_8$ = 28.