Week 5-Radical Equations

Add the square root of the same coefficient

ex: 1-3√5x=-3-2√5x

-3√5x+2√5x=-3-1

-√5x=-4

Than use the way that square both sides of this to get rid of the square root

5x=16

x=16/5

 

Review

\frac{2\sqrt{6}}{\sqrt{7}+\sqrt{5}}

[Than multiply both the top and the bottom by a number , which is goodfor removing the square root of the denominator((\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})=3-2=1)]

=\frac{2\sqrt{6}(\sqrt{7}-\sqrt{5})}{(\sqrt{7}+\sqrt{5})(\sqrt{7}-\sqrt{5})}

=\frac{2\sqrt{42}-2\sqrt{30}}{7-5}

=\frac{2\sqrt{42}-2\sqrt{30}}{2}

=\sqrt{42}-\sqrt{30}

By October 11, 2018.  No Comments on Week 5-Radical Equations  Math 11, Uncategorized   

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