Add the square root of the same coefficient

ex: 1-3√5x=-3-2√5x

-3√5x+2√5x=-3-1

-√5x=-4

Than use the way that square both sides of this to get rid of the square root

5x=16

x=16/5

Review

$\frac{2\sqrt{6}}{\sqrt{7}+\sqrt{5}}$

[Than multiply both the top and the bottom by a number , which is goodfor removing the square root of the denominator(($\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})$=3-2=1)]

=$\frac{2\sqrt{6}(\sqrt{7}-\sqrt{5})}{(\sqrt{7}+\sqrt{5})(\sqrt{7}-\sqrt{5})}$

=$\frac{2\sqrt{42}-2\sqrt{30}}{7-5}$

=$\frac{2\sqrt{42}-2\sqrt{30}}{2}$

=$\sqrt{42}-\sqrt{30}$