This week we learned how to find a solution by using substitution
As an example i will find the solution to 5x-3y=27 and 2x+y=2
the first step is to use one of the equations and isolate one of the variable to one side so 2x+y=2 will turn into y=-2x+2
no we have what y is equal to so step two would be to put y into the other equation so 5x-3y=27 turns into 5x-3(-2x+2)=27
step 3 is to use distributive property to get rid of the brackets so 5x-3(-2x+2)=27 turns into 5x+6x-6=27
step 4 is to combine like terms so 5x+6x-6=27 turns into 11x-6=27
step 5 is to cancel out terms, in this case this means adding 6 to both sides 11x=33
step 6 is to divide to get x by itself
11x/11 33/11
x=3
now that we have x we need to put x into our equation from step one
y=-2(3)+2
now get rid of the brackets
y=-6+2
y=-4
now that we have X and Y we know our solution
(3,-4)
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