Solving Trig Questions | Angus's Blog

$Sin(x) = \frac{15}{30}\\x = Sin^{-1}(\frac{15}{30})\\x = 30^{\circ}$

To isolate $x$ , the Sin has to move over to the other side of the equation, and it becomes $sin^{-1}$

$Cos(30^{\circ}) = \frac{20}{x}\\x = \frac{20}{Cos(30^{\circ})}\\x = 23m$

To isolate $x$ , the $Cos(30^{\circ})$ has to switch with $x$

$Tan(25^{\circ}) = \frac{x}{50}\\x = 50\cdot Tan(25^{\circ})\\x = 23cm$

To isolate $x$ , 50 has to move over to the other side of the equation, and it changes from division to multiplication.

One thought on “Solving Trig Questions”

Very clear explanations about how to isolate the variable – well done! (And good use of latex 🙂

One thought on “Solving Trig Questions”