This week in Math 10 was all about factoring polynomials into binomials. One thing that stuck with me was factoring different squares ( the difference of squares is a squared number subtracted from another squared number. multiplied by a the same squared number as the start of the last binomial added by the same squared number as the last binomial.

Step 1= find the square root of the terms in the equation  

sqaure root of 100= 10

square root of 25= 5

Step 2= write the equation so that they are conjugates (is formed by changing the sign between two terms in a binomial)

Make it so that the square root of 100x^2 is the first term of both binomials and then the square root of 25 is the second term of the binomials, but one MUST have one addition sign and one subtraction sign

Final answer= (10x – 5)(10x+5)

But sometimes we are faced with sometimes difficult equations that look like aren’t perfect square polynomials, but they are hiddin within

Step 1= In my example I was able to divide 2 by both terms and when I did I was left with

x^2 – 25 which is a difference of perfect sqaures

Then I repeated the steps up top and was left with the

FInal Answer= 2(x-5)(x+5) and just have to remember that the two belongs before the two binomials